In 1995, the life expectancy of males in a certain country was 73.7 years. In 2002 it was 77.5 years. Let E represent life expectancy in year t and t represents the number of years since 1995

E(t)=? t + ?
E (11) =? life expectancy of males in 2006

I don't know because I'm trying to figure it out now. Can someone please help me???????

the difference between 1995 and 2001 is 6 years, so you add 6 to 73.7 and you get

0.6t+73.7, that's the first set of answers. Next, you replace the t with the 11 to represent the difference between the next set of years (1995 to 2006) so the next set of answers is
E(11)= 79.2 because you simplify the years 0.5(11)+73.7 and that's how you get your answer :)

sorry about the mix up of 2001 and 2002, but the process is still the same

To find the equation for life expectancy, we need to analyze the given information.

Let's break down the information provided:
- In 1995, the life expectancy of males was 73.7 years.
- In 2002 (which is 7 years after 1995), the life expectancy of males increased to 77.5 years.

We can see that the life expectancy is increasing over time. To determine the relationship between time (t) and life expectancy (E), we need to find the rate of change.

To find the rate of change, we can calculate the difference in life expectancy between the two points and divide it by the number of years between them:
Rate of change = (Life expectancy in 2002 - Life expectancy in 1995) / (Number of years between 2002 and 1995)

Rate of change = (77.5 - 73.7) / 7

Rate of change = 3.8 / 7

Rate of change ≈ 0.5429

Now that we have the rate of change, we can express the equation for life expectancy, E(t), as a linear function of time, t, starting from 1995.

E(t) = (rate of change × t) + (life expectancy in 1995)

E(t) = 0.5429t + 73.7

To find the life expectancy in 2006 (11 years after 1995), we substitute t = 11 into the equation:

E(11) = 0.5429 × 11 + 73.7

E(11) = 5.9719 + 73.7

E(11) ≈ 79.67

Therefore, the life expectancy of males in 2006 is approximately 79.67 years.