posted by Chris on .
A player strikes a hockey puck giving it a velocity of 47.673 m/s. The puck slides across the ice for 0.175 s after which time its velocity is 46.473 m/s.
The acceleration of gravity is 9.8 m/s2 . If the puck strikes the goalie’s pads and stops in a distance of 4.39 cm, what average force is exerted on the pads?
Answer in units of N.
Sorry, I am not interested in the original speed or gravity or how long it slid across the ice.
However I do need the mass of the puck.
F = m *(change in velocity)/time
time = distance/average speed stopping
distance = .0439m
average speed stopping = 23.236 m/s
time = .0439/23.236 seconds to stop
F = m (46.473) (23.236/.0439)
so if I only knew m, I could help you.
However as you can sense, the heavier the puck, the more the force.
The mass of the hockey puck is 185 grams. When you said time = distance/average speed stopping, in the equation F = m (46.473)*(23.236/.0439), did you mean this, .0439/23.236.