Posted by Sammy on Friday, January 7, 2011 at 7:02pm.
What is the equation of g(x) if the parent function is f(x) = x^2 and a = 2, h = -5 and k = 7
f(x) = 2(x-5)^2 + 7
F(x) = -3(x+5)^2 + 7
f(x) = 2(x+5)^2 + 7
f(x) = 2(x-5)^2 -7
I think it is 2(x+5)^2 + 7, is that right
Algebra II - Reiny, Friday, January 7, 2011 at 7:08pm
Yes, if you are aiming for the general quadratic in the form
f(x) = a(x-h)^2 + k
Algebra II - drwls, Friday, January 7, 2011 at 7:09pm
Since you do not defined what a, h and k are in terms of any function, I have no idea.
Algebra II - drwls, Friday, January 7, 2011 at 7:10pm
Thanks Reiny. I had never seen that general form before
Algebra II - Reiny, Friday, January 7, 2011 at 7:15pm
Some authors call it the "standard" form of a parabola, it displays the vertex (h,k).
A second point on the graph is needed to find a.
Algebra II-Please clarify one thing for me - Sammy, Friday, January 7, 2011 at 7:15pm
Thanks Reiny-I really appreciate it-I get confused about taking the "h" at times
So if they say h= (-5), then in the equation when it is written,it is positive and vice-versa, correct?
Algebra II - Reiny, Friday, January 7, 2011 at 7:17pm
correct, since in the formula you have
for x-(-5) it would become x+5
for x-(+5) it would become x-5
Algebra II-Thank you - Sammy, Friday, January 7, 2011 at 7:21pm
Thanks alot-At least I get one concept!
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