Posted by Monique on Friday, January 7, 2011 at 11:53am.
I assume you are supposed to do a graphical solution.
first, change each constraint equation to slope/inercept form.
y=-1/2 x+25 and
y=-1/5 x + 16
Now, on an x/y graph, plot those lines. Now what is neat about this solution, the max or min is always at an intersection.
Here, if you assume x>0, and y>0, then you have 4 corners (intersections).
0,0
16,0
0,25 and finally where the lines cross at 30,10
check all those points, I did them in my head.
Then, take your objective function Z, and calculate the value at each of these corners: One will be the max solution.
Now to make a genius of yourself, try a point x,y inside the area, and somewhere along any line, just to prove to yourself the maximum and minimum will always be on a corner.
Related Questions
Algebra - Hi, could someone possibly check my answers to these algebra questions...
college - Maximize P = x + 16y - z subject to 2x + y + z 14 4x + 2y + 3z 28 2x...
linear programming problem - P=-30x+25y Subject to 2x+3y>=30 2x+y<...
Algebra help/ look over please - Can you please look over these and let me know ...
IMPOSSIBLE ALGEBRA >:( - I have to do 10 algebra problems by tomorrow...
math - -5y^3(y-6)+4y^3(y-7) OK - first, distribute -5y^3 to the (y-6). You ...
Math/Algebra - In a certain game, each of 5 players received a score between 0 ...
math-calculus - x^2+9xy+20y^2/x^2+5xy (x+4y)(x+5y)/(x))x+5y) i cancel off x+5y&#...
simplex Method - Solve the linear programming problem by the simplex method. ...
algebra - using substitution how to solve x + 4y = 8 2x + 5y = 29
For Further Reading
