Posted by anu on Friday, January 7, 2011 at 1:36am.
I will assume that by "most economical" you mean
"minimum cost of material for surface area".
let each side of the end square be x, so the radius for the end circles is also x
let the height be y
SA = 2x^2 + 2πxh
but V = 400
400 = πr^2h
h = 400/(πr^2)
SA = 2x^2 + 2πx(400/(πx^2)
= 2x^2 + 800/x
find d(SA)/dx
set it equal to zero and solve for x
straightforward from here.
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