Friday

January 30, 2015

January 30, 2015

Posted by **Erica** on Thursday, January 6, 2011 at 11:55pm.

Thank you!!

- Calc -
**Damon**, Friday, January 7, 2011 at 2:09amI am going to assume that the heat flow into the body is proportional to the difference between body temp T and 30 and rate of change of T is proportional to heat flow .

dT/dt = k (30-T)

try T = -ae^-kt + 30

that is 30 at t-->oo and 30-a at t = 0

so

0 = -a e^-10k + 30

15= -a e^-20k + 30

30 = a e^-10k

45 = a e^-20 k

a = 30/e^-10k

45 = 30 (e^-20k/e^-10k)

45/30 = e^-10k

I think you can take it from there, check arithmetic

- Calc -
**alv**, Monday, August 27, 2012 at 6:03amthe 8th line is the simplification of the sixth line,,, im wandering why it is 45? is the algebraic solution wrong?

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