Posted by **Mathew** on Thursday, January 6, 2011 at 11:38pm.

A line is parallel to 5x+2y-8=0 and has the same y-intercept as x+4y-12=0

Find an equation for the line.

- Math -
**Anonymous**, Friday, January 7, 2011 at 12:28am
first make each into y=mx+b by rearranging

5x+2y-8=0

2y=-5x+8

y=-5/2x +4

and

x+4y-12=0

4y=-x+12

y=-1/4x+3

because the line is parallel to the first equation it will have the same value for the slope (m)

y=-5/2x+b

now use the second equation to solve for the value of y at the y intercept (i.e. we know x is zero, solve y)

y=-1/4x+3

y=-1/4(0)+3

y=3

so the y intercept of our new equation is (x,y)=(0,3)

put this into our new equation to solve for b

y=-5/2x+b

3=-5/2(0)+b

3=b

so our new equation is

y=-5/2x+3

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