Math
posted by Mathew .
A line is parallel to 5x+2y8=0 and has the same yintercept as x+4y12=0
Find an equation for the line.

first make each into y=mx+b by rearranging
5x+2y8=0
2y=5x+8
y=5/2x +4
and
x+4y12=0
4y=x+12
y=1/4x+3
because the line is parallel to the first equation it will have the same value for the slope (m)
y=5/2x+b
now use the second equation to solve for the value of y at the y intercept (i.e. we know x is zero, solve y)
y=1/4x+3
y=1/4(0)+3
y=3
so the y intercept of our new equation is (x,y)=(0,3)
put this into our new equation to solve for b
y=5/2x+b
3=5/2(0)+b
3=b
so our new equation is
y=5/2x+3