(y-1)/2u+x=m what does "u" equal?
(y-1)/2u+x=m
(y-1)/2u=m-x
y-1=2u*(m-x) Divide with (m-x)
2u=(y-1)/(m-x) Divide with 2
u=(y-1)/[2*(m-x)]
1. multiply both sides by 2u+x
2.then multiply the m to (2u+x), so you should end up with y-1=2um+xm
3.then move the xm to the other side of the equation in order to isolate the u term, when you do this you should now have: y-1-xm=2um
4. then divide both sides by the 2m
and that should give you:
u=y-1-xm/2m
To find the value of "u" in the equation (y-1)/2u+x=m, we need to isolate the variable "u" on one side of the equation. Here's how we can do it:
1. Start by multiplying both sides of the equation by 2u to eliminate the denominator:
2u * [(y-1)/2u + x] = 2u * m
2. Distribute 2u to both terms inside the brackets (using the distributive property):
y - 1 + 2ux = 2um
3. Next, we want to isolate the 2ux term by moving the other terms to the other side of the equation. Let's subtract y and add 1 to both sides:
2ux = 2um - y + 1
4. Finally, divide both sides by 2x to solve for "u":
u = (2um - y + 1) / (2x)
Therefore, "u" is equal to (2um - y + 1) / (2x).