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December 19, 2014

December 19, 2014

Posted by **Anonymous** on Thursday, January 6, 2011 at 6:45pm.

- math -
**helper**, Thursday, January 6, 2011 at 7:31pmArea (A) = Lw = 288

Perimeter (P) = 2L + 2w = 68

L = length, w = width

Solve 2L + 2w = 68 for either L or w

I'll choose L

2L + 2w = 68

2L = 68 - 2w

2L = 2(34 - w)

L = 34 - w

Substitute L = 34 - w, for L in

A = Lw = 288

(34 - w)(w) = 288

34w - w^2 = 288

w^2 - 34w + 288 = 0

w = 18, 16

So, this certain rectangle has dimensions of 18 by 16.

you should be able to calculate the area and perimeter of the new rectangle now. (double the length and width and solve the equations)

- math -
**Ashley**, Monday, November 19, 2012 at 5:08pmr = 2/3t + v, for t

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