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algebra

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Two rectangles have the same width. The length of one is 1 foot longer than the width. The length of the other is 2 feet longer than the width. The larger rectangle has 5 more square feet than the smaller. What is the width of the rectangles

  • algebra -

    Area=lw
    w=width
    w=width of 1st, w=width of 2nd (since their widths are equal)
    l=length
    l=w+1 length of 1st
    l=w+2 length of 2nd
    Area of 1st = w(w + 1)
    Area of 2nd = w(w + 2) - 5
    Therefore,
    w(w + 1) = w(w + 2) - 5
    Solve for w

  • algebra -

    if the length is 7 meters longer than its width. what is the width of the object if the perimeter is equal to 98

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