Posted by **Anonymous** on Thursday, January 6, 2011 at 10:45am.

Two rectangles have the same width. The length of one is 1 foot longer than the width. The length of the other is 2 feet longer than the width. The larger rectangle has 5 more square feet than the smaller. What is the width of the rectangles

- algebra -
**helper**, Thursday, January 6, 2011 at 11:37am
Area=lw

w=width

w=width of 1st, w=width of 2nd (since their widths are equal)

l=length

l=w+1 length of 1st

l=w+2 length of 2nd

Area of 1st = w(w + 1)

Area of 2nd = w(w + 2) - 5

Therefore,

w(w + 1) = w(w + 2) - 5

Solve for w

- algebra -
**k**, Wednesday, January 19, 2011 at 12:58pm
if the length is 7 meters longer than its width. what is the width of the object if the perimeter is equal to 98

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