AP PHYSICS MECH.
posted by vm on .
A simple pendulum, consists of an object suspended by a string. The object is assumed to be a particle. The string, with its top end fixed, has negligible mass and does not stretch. In the absence of air friction, the system oscillates by swinging back and forth in a vertical plane. If the string is 2.35 m long and makes an initial angle of 27.5° with the vertical, calculate the speed of the particle at the following positions.
(a) at the lowest point in its trajectory
(b) when the angle is 15.0°

Energy conservation indicates that
M g L (1cos A) + (1/2)M V^2
= M g L (1cos Amax)
at any angle location A. M cancels out.
Your Amax angle is 27.5 degrees, so:
g L (1  cosA) + V^2/2 = 0.11299 gL
Use that equation to solve for V at any angle A 
Thank you..