The original data is given in terms of area, but the width is not in the same units.
If area 1 = x, then area 2 = 2x and area 3 = x + 3.
If the total area = 18 square inches, then
x + 2x + x + 2 = 18
Then you can solve for x.
4x + 2 = 18
4x = 16
x = 4
I'll answer since this is unanswered, but, I don't think this is how a third grade student is expected to do this problem.
w = width of web
w = size in inches of the 2nd web
2w = size in inches of the 1st web
2w + 3 = size in inches of the 3rd web
1'6" = 18 inches
w + 2w + (2w + 3 ) = 18
5w + 3 = 18
5w = 15
w = 3
1st web = 3 inches
2nd web = 6 inches
3rd web = 9 inches
Total combined width = 18 inches
I would be very interested to learn how a grade 3 teacher would handle this type of question without relying on algebraic methods such as shown above by
PsyDAG and helper.
This sure looks like some fancy advanced grade 3 stuff.
what is symmetry
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