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Posted by **Dominique** on Thursday, January 6, 2011 at 12:25am.

Please provide explanation along with answer. Thank you in advance.

- 3rd grade Math -
**PsyDAG**, Thursday, January 6, 2011 at 12:12pmThe original data is given in terms of area, but the width is not in the same units.

If area 1 = x, then area 2 = 2x and area 3 = x + 3.

If the total*area*= 18 square inches, then

x + 2x + x + 2 = 18

Then you can solve for x.

4x + 2 = 18

4x = 16

x = 4

- 3rd grade Math -
**helper**, Thursday, January 6, 2011 at 12:18pmI'll answer since this is unanswered, but, I don't think this is how a third grade student is expected to do this problem.

w = width of web

w = size in inches of the 2nd web

2w = size in inches of the 1st web

2w + 3 = size in inches of the 3rd web

1'6" = 18 inches

w + 2w + (2w + 3 ) = 18

5w + 3 = 18

5w = 15

w = 3

1st web = 3 inches

2nd web = 6 inches

3rd web = 9 inches

Total combined width = 18 inches

- 3rd grade Math -
**Reiny**, Thursday, January 6, 2011 at 12:46pmI would be very interested to learn how a grade 3 teacher would handle this type of question without relying on algebraic methods such as shown above by

PsyDAG and helper.

This sure looks like some fancy advanced grade 3 stuff.

- 3rd grade Math -
**Elizabeth**, Monday, January 10, 2011 at 5:32pmwhat is symmetry

- 3rd grade Math -
**Anonymous**, Tuesday, June 12, 2012 at 3:55pmwhats up

- 3rd grade Math -
**taylor**, Wednesday, November 13, 2013 at 8:57pmyou stupid

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