Approximate the gravitational force of attraction between a 46.0 kg girl and a 60.0 kg boy if they are sitting 2.5 m apart in physics class.

N

Review and apply Newtons universal layw of gravity.

F = G*M1*M2/R^2

Look up G if necessary. Surely it has been mentioned in your course materials

To approximate the gravitational force of attraction between the girl and the boy, we can use Newton's law of universal gravitation. The equation is given by:

F = (G * (m1 * m2)) / r^2

Where:
- F is the gravitational force of attraction between the objects
- G is the gravitational constant (approximately 6.67430 × 10^-11 m^3 kg^-1 s^-2)
- m1 and m2 are the masses of the objects (in this case, the girl and the boy)
- r is the distance between the objects (in this case, 2.5 meters)

Plugging in the values:

F = (6.67430 × 10^-11) * ((46.0) * (60.0)) / (2.5^2)

Now, let's calculate the answer.

F = (6.67430 × 10^-11) * (2760.0) / (6.25)

F = 1.472 x 10^-9

Therefore, the approximate gravitational force of attraction between the girl and the boy is approximately 1.472 x 10^-9 Newtons.