How do you express
(sq.root of 3 + 1)(sq.root of 3 - 1) in simplest form?
(√3 + 1)(√3 - 1)
= 3 - 1
= 2
this has the pattern of the difference of squares just like
(a+b)(a-b) = a^2 - b2
(sq.root of 3 + 1)(sq.root of 3 - 1) in simplest form?
= 3 - 1
= 2
this has the pattern of the difference of squares just like
(a+b)(a-b) = a^2 - b2