February 20, 2017

Homework Help: Biochemistry

Posted by Rose on Wednesday, January 5, 2011 at 10:06pm.

How do you prepare 100 mL of a 0.1 M TRIS-HCl buffer with a pH 7.4 using solid TRIS base (MW 121.1) and 1 M hydrochloric acid?

I started with

pH=pKa + log ([Tris]/[Tris+]
[Tris]/[Tris+]= 10^(7.4-8.06]=0.219
so 0.219:1 ratio with 2.219 total

[Tris}=(0.219/1.219)*0.1 M= 0.018 M
[Tris+]= (1/1.219)*0.1 M= 0.082 M

M_[Tris]= (0.018M)(0.1L)= (0.0018 mol* 121.1 g/mol)= 0.218 g Tris

I'm not sure if this is correct but my main issues is how do I determine the amount of HCl I will need to add?

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