Posted by **Tiara** on Wednesday, January 5, 2011 at 6:25pm.

Five pulses are generated every 0.094 s in a tank of water. What is the speed of propagation of the wave if the wavelength of the surface wave is 1.14 cm?

can you break it down please.

- Physics -
**Henry**, Thursday, January 6, 2011 at 10:15pm
F = 5 / 0.094 = 53.2 Pulses/s =

frequency of pulses.

T = 1/F = 1/53.2

L = VT,

V = L/T = LF,

V = 1.14cm * 53.2pulses/s = 60.6cm/s.

L = wavelength in cm.

F = frequency in pulses / s.

T = Period of frequency.

.

## Answer This Question

## Related Questions

- physics - A water wave is generated in a ripple tank by an oscillator that ...
- physics - A certain transverse wave is described by the equation y(x,t) = (6.50 ...
- College Physics - A certain transverse wave is described by the equation y(x,t...
- physics - The distance between two nearest nodes of a standing wave is 22.9 cm. ...
- Physics - A water wave is generated in a ripple tank by an oscillator that ...
- physic - The distance between two nearest nodes of a standing wave is 16.3 cm. ...
- Physic - The distance between two nearest nodes of a standing wave is 17.3 cm. ...
- Physics - Two kids sitting on opposite sides of a small lake use sticks to beat ...
- physics - A water-skier is moving at a speed of 16.7 m/s. When she skis in the ...
- Physics - Not sure where to begin with this question--any help appreciated! Two ...

More Related Questions