Post a New Question


posted by .

A hiker shouts toward a vertical cliff 675 m away. The echo is heard 4.00 s later.

(a) What is the speed of sound of the hiker's voice in air? m/s
(b) The wavelength of the sound is 0.774 m. What is its frequency? Hz
(c) What is the period of the wave?

  • Physics -

    (a) It depends upon the air temperature. Usually about 340 m/s is used for the sound speed.

    (b) frequency =
    (sound wave speed)/(wavelength)
    = 340/0.774
    = ___ Hz

    (c) Period = 1/(frequency)
    (in seconds)

  • Physics -

    thanks, you were right.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question