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May 25, 2015

Homework Help: Math

Posted by Ann on Wednesday, January 5, 2011 at 5:29pm.

How many odd four-digit numbers, all of the digit different can be formed from the digits 0 to 7, if there must be a 4 in the number?

My Answer:

There are four options for the last digit (1, 3, 5, or 7). One of the other three digits only has 1 option (for the 4). One of the other remaining digits will have 6 options and the final digit will have 5 options (because they can't repeat the first two) Therefore, the answer is:

4*1*5*6=120

I do not have much confidence in my answer. Could someone please tell me if I did this right? Thanks for your help.

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