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If a ball is thrown into the wall at 14 m/s and comes off at 6 m/s, what is change of velocity of the ball?

I think it would be 14-6 = (-8 m/s) Is that correct?

from +14 to -6 is -22

final = -6
original = 14
final - original = -6 -14 = -22

Shouldn't it be -20,not -22

Damon helped me to solve this problem but I think it adds up to -20 not -22, correct?

Change in velocity = Vf-Vi =6 - 14 = -8

m/s.

Yes, you are correct. The change in velocity of the ball can be calculated by subtracting the initial velocity from the final velocity. In this case, the initial velocity is 14 m/s and the final velocity is 6 m/s. Thus, the change in velocity would be 6 m/s - 14 m/s = -8 m/s. The negative sign indicates that the velocity has decreased.