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Posted by on Wednesday, January 5, 2011 at 2:01pm.

5/4x+1/8x=5/8+x

  • algebra - , Wednesday, January 5, 2011 at 2:06pm

    Please use parentheses
    do you mean
    (5/4)x
    or
    5/(4x) etc

  • algebra - , Wednesday, January 5, 2011 at 2:19pm

    5/4x+1/8x=5/8+x

    10/8x + 1/8x = 5/8 + x
    11/8x = 5/8 + x
    11/8x + x = 5/8
    19/8x = 5/8
    x = (5/8) / (19/8)
    x = (5/8)* (8/19)
    x = 40/152 = 5/19

  • algebra - , Wednesday, January 5, 2011 at 2:52pm

    Asuming the problem to be
    5/4x + 1/8x = 5/8 + x


    (10 + 1) / 8x = (5 + 8x) / 8

    ie. 11/ 8x = (8x + 5) / 8

    11 = 8x (8x +5) / 8

    ie. 11 = 8x ^2 + 5x

    We will now have to handle it as a quadratic equation:

    8x ^2 + 5x - 11 = 0

    Apply the formula to get the roots:

    (-b + Sqrt ( b^2 - 4ac) ) / 2a
    -

    Hope this clarifies enough!

  • algebra - , Wednesday, January 5, 2011 at 3:06pm

    If you meant
    5/(4x) + 1/(8x) = 5/(8+x) then follow Kay's solution

    if you meant it the way you typed it, the follow Ms. Sue's way, except I noted an error in her 3rd line, should have been ....
    11/8x - x = 5/8
    3/8x = 5/8
    x = (5/8) / (3/8)
    x = (5/8)* (8/3)
    x = 40/152 = 5/3

  • algebra - , Wednesday, January 5, 2011 at 3:35pm

    Oops! Thanks for the correction, Reiny.

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