Posted by beth on Wednesday, January 5, 2011 at 2:00pm.
- algebra - bobpursley, Wednesday, January 5, 2011 at 2:02pm
subtract the second equation from the first...
I am not certain on your second equation, an equals is missing.
- algebra - Kay, Wednesday, January 5, 2011 at 3:57pm
I tried and verified the equation with the following assumption to make it work.
3r - 5s = -14
3r +3s = 56
subtract the second equation from first equation:
You will get -8s = -70
s = 70/8
substitute s in any of the original problem equations to get the value of r.
3r = -14 + 5s
3r = -14 + 5 (70/8)
= (-112 + 350)/8
3r = 119/4
r = 119/12
To verify the values - apply the values to one of the equations to hold true.
3r -5s should be equal to -14
= 3 (119/12) - 5 (70/8)
= 119/4 - 350/8
= (238 - 350) / 8
So we are good!
Additional note regarding posting of your question:
So, your problem statement should be
3r + 3s = 56
Hope this clarifies!
Answer this Question
More Related Questions
- Algebra - I am getting ready to start an Algebra class for the first time and I ...
- SHAY - THE MATH QUESTION IS IT ALGEBRA , PRE ALGEBRA' OR GEOMETRY? Quadriatic ...
- Algebra 1A - How is algebra a useful tool? what concepts investigated in algebra...
- Algebra I - So- im trying to help my little brother out with his Algebra- but ...
- Algebra-still need some help - Homework Help Forum: Algebra Posted by Jena on ...
- algebra 1 - at a certain high school,350 students are taking algebra. the ratio ...
- algebra - Is there a site or someone who can help me, im not getting the basic ...
- 7th grade - There are at least 5 more than twice as many students taking algebra...
- algebra 2 - Posted by hellogoodbie on Saturday, January 16, 2010 at 3:24pm. ...
- Algebra II - ok now this is an algebra 2 problem... I have goten far down to ...