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Posted by **beth** on Wednesday, January 5, 2011 at 2:00pm.

- algebra -
**bobpursley**, Wednesday, January 5, 2011 at 2:02pmsubtract the second equation from the first...

3r-3r-5s-3s=-14+?56

I am not certain on your second equation, an equals is missing.

- algebra -
**Kay**, Wednesday, January 5, 2011 at 3:57pmI tried and verified the equation with the following assumption to make it work.

3r - 5s = -14

3r +3s = 56

subtract the second equation from first equation:

You will get -8s = -70

s = 70/8

substitute s in any of the original problem equations to get the value of r.

3r = -14 + 5s

3r = -14 + 5 (70/8)

= (-112 + 350)/8

= 238/8

3r = 119/4

r = 119/12

To verify the values - apply the values to one of the equations to hold true.

3r -5s should be equal to -14

= 3 (119/12) - 5 (70/8)

= 119/4 - 350/8

= (238 - 350) / 8

= -112/8

= -14

So we are good!

Additional note regarding posting of your question:

So, your problem statement should be

3r + 3s = 56

Hope this clarifies!

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