math
posted by w on .
two baseball players bat first and second in the lineup the first batter has on base percentage of 0.46 the second batter has an on base percentage of 0.31 if someone is on base but only 0.23 if the bases are empty at the start of the game what is the probability that both players get on base?

The probability of both/all events occurring is found by multiplying the probabilities of the individual events.
.46 * .31 = ?