Posted by JOHN on Wednesday, January 5, 2011 at 12:21am.
It hits the floor with velocity of
V = g*1.2s = 11.8 m/s
Use that and the mass to get the momentum, M*V = 2.94 kg m/s
The average force applied by the floor during deceleration (t' = 0.1 s) is M*V/t' = ___ Newtons
(impulse = F*t' = momentum change)
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