Posted by alison on Tuesday, January 4, 2011 at 7:08pm.
the perimeter of a rectangle is 22 meters, and the perimeter of the triangle is 12 meters. find the dimensions of the rectangle?

math  Marth, Tuesday, January 4, 2011 at 7:12pm
Let l be the length, and w be the width, of the rectangle.
The perimeter of the rectangle is 2(l+w).
The perimeter of the triangle is l+w+sqrt(l^2+w^2). sqrt(l^2+w^2) is the hypotenuse of the triangle.
There are two equations and two variables. Find l and w. 
math  alison, Tuesday, January 4, 2011 at 7:16pm
the hypotneuse is 5 meters so how could i figure the dimensions of the rectangle out?

math  Marth, Tuesday, January 4, 2011 at 7:19pm
The perimeter of the rectangle is 22m. So 2(l+w) = 22.
l+w = 11
l = 11w
Also, l^2+w^2 = 5^2 by Pythagorean Theorem.
Substitute in l = 11w: (11w)^2+w^2=5^2 
math  alison, Tuesday, January 4, 2011 at 7:24pm
i have the deminsions of the rectangle but i need to know how to get it , the deminsions are 8m by 3m

math  Marth, Tuesday, January 4, 2011 at 7:26pm
Are you referring to the triangle formed by the diagonal of the rectangle and two of its sides? If the dimensions are 8m by 3m, the hypotenuse of said triangle cannot be 5m.

math  alison, Tuesday, January 4, 2011 at 7:29pm
im referring to the deminsions of a rectangle with a triangle with a hypotneuse of 5m in the top right corner

math  Marth, Tuesday, January 4, 2011 at 7:33pm
Is the base of the triangle the width of the rectangle, and the height of the triangle half the length of the rectangle?

math  alison, Tuesday, January 4, 2011 at 7:35pm
yes it certainly is

math  Marth, Tuesday, January 4, 2011 at 7:37pm
Ok. Then the perimeter of the triangle is w + l/2 + 5.
So w+l/2+5 = 12m, and 2(l+w)=22m. 
math  alison, Tuesday, January 4, 2011 at 7:41pm
thank you so very much you are awesome i wish you were my math teacher!

math  alison, Tuesday, January 4, 2011 at 7:45pm
you are going to end up hating me i am really bad at dimensions so please bear with me.
a dorm room your sister is considering seems small.the room is rectangular and has a perimeter of 42 feet. the room is 4 feet longer than its width. what are the dimensions of the room? 
math  Ms. Sue, Tuesday, January 4, 2011 at 7:54pm
Alison  please post your last question as a separate post.

math  alison, Tuesday, January 4, 2011 at 7:54pm
nevermind i got it thanks anyway!