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October 30, 2014

October 30, 2014

Posted by **liza** on Tuesday, January 4, 2011 at 4:58pm.

- math -
**MathMate**, Tuesday, January 4, 2011 at 7:05pmFor a geometric series,

the nth term is

t(n)=ar^{n}

So

t(3)=ar³

t(6)=ar^{6}

t(6)/t(3)

= ar^{6}/ ar³

= r^{6-3}

= r³

Solve for r in

r³=9375/(-75)

r=(-125)^{1/3}

=-5

A = t(3)/r³

= -75/(-5)³

= 3/5

and first term

= t(1)

= Ar

= 3/5(-5)

= -3

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