Posted by **Anonymous** on Monday, January 3, 2011 at 10:21pm.

A 48.0 kg diver steps off a 10.0 m high diving board and drops straight down into the water. If the diver comes to rest 5.0 m below the surface of the water, determine the average resistance force exerted on the diver by the water.

N

- physics -
**drwls**, Monday, January 3, 2011 at 10:31pm
Gravity continues to work on the diver as he descends under water. This mst be taken into account.

The total potential energy (P.E) loss of the diver at greatest depth is M g (10 + 5) = 7056 J

Work done by the water on the diver, or of the diver upon the water, is equal to that P.E. loss at the greatest depth.

Thus 7056 J = F*5m

where F is the average force (averaged over distance, not time).

F = 1411 N

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**Joelle**, Tuesday, January 4, 2011 at 11:51am
Don't know the answer but posted it on the Diving News Facebook page: diving News - By flipnrip

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**Joelle**, Tuesday, January 4, 2011 at 9:21pm
Roughly twice the gravitational acceleration of 9.8 to stop in have the time. Given F=MA then F = 48*19.6 or about 950 (kg*m/(S^2)).

SOmeone helped on the facebook page: diving news by flipnripcom

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**Coach Kev**, Sunday, January 23, 2011 at 10:23pm
353.16lb of resistance to stop at 5M (that is for the distance of their feet hitting to 5M of their feet depth). m*g*(10+5) = F*5

F = 3*m*g = 1412N = 353.16lb

...A far better calculation uses the drag equation: Fd=0.5*rho*A*Cd*v^2

You can find the force at each point through the water instead of just the average. However, it is difficult to say how accurate it is-would need a little video analysis to justify it. I will put up a note with the complete analysis when I get a chance.

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