math
posted by Casey on .
An angry construction worker throws his wrench downward from a height of 128 feet with an
initial velocity of 32 feet per second. The height of the wrench above the ground after t seconds is given
by S(t)= 16t^2  32t + 128.
a) What is the height of the wrench after 1 second?
b) How long does it take for the wrench to reach the ground?

a) replace t with 1
b) solve
16t^2  32t + 128 = 0
or , after dividing all terms by 16,
t^2 + 2t  8 = 0