Saturday

March 28, 2015

March 28, 2015

Posted by **Rachel** on Monday, January 3, 2011 at 9:14pm.

- Algebra -
**Reiny**, Monday, January 3, 2011 at 9:21pmAn easier way than what?

In these kind of problems you have to find which of the three variables, either time, distance or rate, are equal.

In this case, at the moment the 2nd train catches up to the first, they will have gone the same distance.

let the time taken for the 2nd train to catch the first be t hours

so distance covered by the slower train = 30(t+1)

distance covered by the faster train = 50t

50t = 30(t+1)

20t = 30

t = 3/2 hours or 1.5 hours

the faster train left at 5:00 and took 1.5 hours, so it will catch the slower at 6:30 pm

**Answer this Question**

**Related Questions**

Math - 5) A freight train leaves a station traveling at 32 km/h. Two hours later...

Algebra - A freight train leaves Chicago traveling West at 35 mph. An hour later...

math - Train leaves a stationa traveling at 60 miles per hour. Eight hours later...

algebra - A train leaves the station at 9:00 pm traveling east at 36 miles per ...

math - A train leaves the station at 9:00 pm traveling east at 36 miles per ...

algebra - a passenger train traveling at 50 mph leaves the station 6 hours after...

math - a freight train leaves detroit traveling east at a speed of 65mph. one ...

algebra - I need help with a word problem. Trains A and B are traveling in the ...

pre algebra - train A leaves a station at 1:15 PM,traveling 60 mph.Train B ...

Algebra - Train A and B are traveling in the same direction on parallel tracks. ...