Posted by Rachel on Monday, January 3, 2011 at 9:14pm.
Is there an easier way to do this? "A freight train leaves a station at 4:00 p.m. traveling at 30 kilometers per hour. A passenger train leaves 1 hour later, traveling at 50 kilometers per hour. At what time will the passenger train overtake the freight train?

Algebra  Reiny, Monday, January 3, 2011 at 9:21pm
An easier way than what?
In these kind of problems you have to find which of the three variables, either time, distance or rate, are equal.
In this case, at the moment the 2nd train catches up to the first, they will have gone the same distance.
let the time taken for the 2nd train to catch the first be t hours
so distance covered by the slower train = 30(t+1)
distance covered by the faster train = 50t
50t = 30(t+1)
20t = 30
t = 3/2 hours or 1.5 hours
the faster train left at 5:00 and took 1.5 hours, so it will catch the slower at 6:30 pm
Answer This Question
Related Questions
 Algebra  A train leaves the station at 8 a.m. and averages 40 miles per hour ...
 Algebra  A train leaves the station at 8 a.m. and averages 40 miles per hour ...
 college algebra  A freight rain leaves a station and travels north at a ...
 algebra  A train leaves the station at 9:00 pm traveling east at 36 miles per ...
 math  Train leaves a stationa traveling at 60 miles per hour. Eight hours later...
 math  A train leaves the station at 9:00 pm traveling east at 36 miles per ...
 Algebra  A freight train leaves Chicago traveling West at 35 mph. An hour later...
 Math  5) A freight train leaves a station traveling at 32 km/h. Two hours later...
 algebra  A train leaves Buffalo traveling west at 60 miles per hour. An hour ...
 algebra  I need help with a word problem. Trains A and B are traveling in the ...
More Related Questions