5x^5-x^4-5x^3+x^2-30x+6=
What is your question?
Please only post your questions once. Repeating posts will not get a quicker response. In addition, it wastes our time looking over reposts that have already been answered in another post. Thank you.
The equation you provided is a polynomial equation. To solve this equation, we need to find the values of x that make the equation true. However, the equation you provided is not set equal to anything, so I assume you are looking for the values of x that make the expression equal to zero.
To solve this equation: 5x^5 - x^4 - 5x^3 + x^2 - 30x + 6 = 0, we can follow these steps:
Step 1: Rearrange the equation in descending order of the exponent of x:
5x^5 - x^4 - 5x^3 + x^2 - 30x + 6 = 0
Step 2: Factor out common terms, if possible:
(x^2 - 1) (5x^3 - 6) (x - 1) = 0
Step 3: Set each factor equal to zero and solve for x:
x^2 - 1 = 0
This yields two solutions:
x = 1 and x = -1
5x^3 - 6 = 0
Solving for x will give us the third solution:
x = ∛(6/5)
x - 1 = 0
Solving for x will give us the fourth solution:
x = 1
Therefore, the solutions to the equation 5x^5 - x^4 - 5x^3 + x^2 - 30x + 6 = 0 are x = 1, x = -1, and x = ∛(6/5).