Posted by markees on .
You have a 10 M acidic solution. However, you need that solution to be 0.25 M. How many ml of 10 M should be diluted to obtain 300 ml of 0.25 M acid solution?
The dilution formula is
mL x M = mL x M
A solution of ethanol (C2H5OH) in water is prepared by dissolving 87.4 mL of ethanol (density = 0.79 g/cm3) in enough water to make 250.0 mL of solution. What is the molarity of the ethanol in this solution?