Post a New Question

Math

posted by on .

Find an algebraic expression for f'

f(x)= 2e^x+ pi
f(x)=e^5-4e^x
f(x)=e^x+x^e+e
f(x)= e^pi +pi^x+ x^pi

I didn't understand these at all

  • Math - ,

    2 e^x

    -4 e^x because e^5 is a constant

    e^x + e x^(e-1) because e is constant

    pi^x ln pi + pi x^(pi-1) because e^pi is constant

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question