Math
posted by Mike on .
Find an algebraic expression for f'
f(x)= 2e^x+ pi
f(x)=e^54e^x
f(x)=e^x+x^e+e
f(x)= e^pi +pi^x+ x^pi
I didn't understand these at all

2 e^x
4 e^x because e^5 is a constant
e^x + e x^(e1) because e is constant
pi^x ln pi + pi x^(pi1) because e^pi is constant