Posted by **Aparna** on Monday, January 3, 2011 at 1:12am.

A hard ball dropped from a height of 1 m in earth’s gravitational field bounces to a height of 95 cm. What

will be the total distance traversed by the ball?

- Physics -
**drwls**, Monday, January 3, 2011 at 1:21am
Counting all bounces? That would be

100 (1 + 2*0.95 + 2*0.95^2 + 2*0.0.95^3 + ... centimeters. That is an infinite series, and assumes that the down-to-up ratio is always 0.95.

That can be written as

100*(2 + 2*0.95 + 2*0.95^2 + 2*0.0.95^3....) - 100

or, in closed form, as

200[1/(1-0.95)] - 100

= 3900 cm

- Physics -
**Dr Russ**, Monday, January 3, 2011 at 1:22am
A question like this was answered recently. I'll try to find a link.

- Physics -
**Dr Russ**, Monday, January 3, 2011 at 1:23am
drwls is faster than me!!

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