Posted by Aparna on Monday, January 3, 2011 at 1:12am.
A hard ball dropped from a height of 1 m in earth’s gravitational field bounces to a height of 95 cm. What
will be the total distance traversed by the ball?

Physics  drwls, Monday, January 3, 2011 at 1:21am
Counting all bounces? That would be
100 (1 + 2*0.95 + 2*0.95^2 + 2*0.0.95^3 + ... centimeters. That is an infinite series, and assumes that the downtoup ratio is always 0.95.
That can be written as
100*(2 + 2*0.95 + 2*0.95^2 + 2*0.0.95^3....)  100
or, in closed form, as
200[1/(10.95)]  100
= 3900 cm

Physics  Dr Russ, Monday, January 3, 2011 at 1:22am
A question like this was answered recently. I'll try to find a link.

Physics  Dr Russ, Monday, January 3, 2011 at 1:23am
drwls is faster than me!!
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