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November 24, 2014

November 24, 2014

Posted by **Tabby** on Monday, January 3, 2011 at 12:26am.

- Trig -
**Reiny**, Monday, January 3, 2011 at 9:42amyou should be familiar with the general equation of a sine function for the above problem.

Just insert the values, the only value needing any consideration is the period

period = 2π/k, k = 2π/(2π) = 1

so

y = (1/7) sin 1(Ø - 6π) + 10 or

y = (1/7) sin(Ø - 6π) + 10

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