Sunday

December 28, 2014

December 28, 2014

Posted by **Giselle** on Sunday, January 2, 2011 at 10:23pm.

A) .882

B) .961

C) .039

D) .079

- Statistics and Probability -
**Reiny**, Sunday, January 2, 2011 at 10:48pmprob of causing illness = .3

prob of not causing illness = .7

so you want

prob(7of 12will cause illness) + prob(8of 12will cause illness)+ ... + prob(12of 12will cause illness)

= C(12,7)(.3)^7(.7)^5 + C(12,8)(.3^8)(.7^4) + ... +C(12,12)(.3^12)

you do the button pushing.

- Statistics and Probability -
**Giselle**, Sunday, January 2, 2011 at 10:50pmThank you Soo much!

- Statistics and Probability -
**Reiny**, Sunday, January 2, 2011 at 10:53pmwelcome

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