what is the percent by mass of nitrogen in (NH4)2CO3? how do you do this ?
(mass N/total mass)*100 = ??
[(2*14)/(molar mass (NH4)2CO3)] * 100 =
To find the percent by mass of nitrogen in (NH4)2CO3, you need to calculate the molar mass of nitrogen in the compound and divide it by the molar mass of the entire compound. Here's the step-by-step process:
1. Determine the molar mass of nitrogen (N): Nitrogen has an atomic number of 7 and a molar mass of approximately 14.01 g/mol.
2. Calculate the molar mass of the entire compound:
(NH4)2CO3 contains two ammonium ions (NH4+) and one carbonate ion (CO32-). The molar mass of one ammonium ion is 18.04 g/mol (14.01 g/mol for nitrogen plus 4 hydrogen atoms, each with a molar mass of approximately 1.01 g/mol). The carbonate ion has a molar mass of 60.01 g/mol (12.01 g/mol for carbon plus 3 oxygen atoms, each with a molar mass of approximately 16.00 g/mol). Therefore, the molar mass of (NH4)2CO3 is:
(2 ammonium ions x 18.04 g/mol) + (1 carbonate ion x 60.01 g/mol) = 132.14 g/mol.
3. Calculate the mass of nitrogen in the compound: Since (NH4)2CO3 has two nitrogen atoms, we need to multiply the molar mass of nitrogen by two:
2 x 14.01 g/mol = 28.02 g.
4. Calculate the percent by mass of nitrogen: Divide the mass of nitrogen by the molar mass of the entire compound, and then multiply by 100 to get the percentage:
(28.02 g / 132.14 g) x 100 = 21.20%.
Therefore, the percent by mass of nitrogen in (NH4)2CO3 is approximately 21.20%.