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Posted by on Sunday, January 2, 2011 at 7:39pm.

What linear speed must an Earth satellite have to be in a circular orbit at an altitude of 208 km above Earth's surface? (b) What is the period of revolution?

I got a to be 7786 m/s^2 but im not sure how to get b.

  • physics - , Sunday, January 2, 2011 at 7:51pm

    m/s is speed
    m/s^2 is acceleration

    G m Me/r^2 = m v^2/r

    G Me/r = v^2

    r = .208*10^6 + 6.38*10^6 = 6.59 * 10^6 meters

    v^2 = 6.67*10^-11*5.98*10^24/6.59*10^6
    v^2 = 6.05*10^7 = 60.5*10^6
    v = 7780 m/s agree
    now
    circumference = 2 pi r
    time = circumference/speed

  • physics - , Sunday, January 2, 2011 at 8:22pm

    is the time is seconds or minutes?

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