Monday

July 28, 2014

July 28, 2014

Posted by **Joshua** on Sunday, January 2, 2011 at 7:32pm.

- algebra -
**DrBob222**, Sunday, January 2, 2011 at 8:58pmLet x = the 55 mph car.

and y = the 60 mph car.

I have tried to draw it below using periods as spacers (since these boards don't recognize more than one space.).

(55 mph)x->................<-y (60 mph)

........|--------------------|

........|...d..|....500-d....|

So car x will go a distance of d and car y will go a distance of 500-d. The time will be d = rate*time and time=d/r. The time will be equal; therefore,

(d/55) = (500-d)/60

Solve for d which will tell you how far car x and car y traveled, then use d = r*t and some for time. My calculations give a little over 4 hours for each. Post your work if you get stuck.

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