Posted by Joshua on Sunday, January 2, 2011 at 7:32pm.
Let x = the 55 mph car.
and y = the 60 mph car.
I have tried to draw it below using periods as spacers (since these boards don't recognize more than one space.).
(55 mph)x->................<-y (60 mph)
........|--------------------|
........|...d..|....500-d....|
So car x will go a distance of d and car y will go a distance of 500-d. The time will be d = rate*time and time=d/r. The time will be equal; therefore,
(d/55) = (500-d)/60
Solve for d which will tell you how far car x and car y traveled, then use d = r*t and some for time. My calculations give a little over 4 hours for each. Post your work if you get stuck.
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