Friday

January 30, 2015

January 30, 2015

Posted by **Erica** on Sunday, January 2, 2011 at 4:35pm.

I got the -cos(3x+4) part, but do you have to integrate the 3x+4 too? Does chain rule apply?

- Calc -
**Marth**, Sunday, January 2, 2011 at 4:53pmUse u substitution.

Let u = 3x+4. Then du = 3dx.

Substitute into the integral.

= (1/3)∫sin(u)du

= -(1/3)cos(u)+C

= -(1/3)cos(3x+4)+C

**Answer this Question**

**Related Questions**

Math integrals - What is the indefinite integral of ∫ [sin (π/x)]/ x^...

calculus II - ∫ tan^2 x sec^3 x dx If the power of the secant n is odd, ...

calculus - Let z = ∫e^(sin(t))dt from x to y a = x b = y I tried thinking ...

calculus - Let z = ∫e^(sin(t))dt from x to y a = x b = y I tried thinking ...

calculus - Let z = ∫(e^sin(t)dt) from x to y a = x b = y I tried thinking ...

calculus - Find dz/dy and dz/dx Let z = ∫e^(sin(t))dt from x to y a = x b...

Math, derivatives - f(x) = x² + 2Cos²x, find f ' (x) a) 2(x+cos x) b) x - sin x ...

Calculus AP - Use the table of integrals to find int cos^4 3x dx I found the ...

Calculus - I have y = sin^2(3^(x)) which I rewrite as y = (sin(3^(x)))^2 I got ...

Calc I - How do I find the derivative for the sqrt(sin(e^(x^3)*cos(x)))??? I ...