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posted by on .

How do you solve ∫sin(3x+4)dx?
I got the -cos(3x+4) part, but do you have to integrate the 3x+4 too? Does chain rule apply?

  • Calc - ,

    Use u substitution.
    Let u = 3x+4. Then du = 3dx.
    Substitute into the integral.
    = (1/3)∫sin(u)du
    = -(1/3)cos(u)+C
    = -(1/3)cos(3x+4)+C

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