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October 23, 2014

October 23, 2014

Posted by **Erica** on Sunday, January 2, 2011 at 4:35pm.

I got the -cos(3x+4) part, but do you have to integrate the 3x+4 too? Does chain rule apply?

- Calc -
**Marth**, Sunday, January 2, 2011 at 4:53pmUse u substitution.

Let u = 3x+4. Then du = 3dx.

Substitute into the integral.

= (1/3)∫sin(u)du

= -(1/3)cos(u)+C

= -(1/3)cos(3x+4)+C

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