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March 3, 2015

March 3, 2015

Posted by **hawkins** on Sunday, January 2, 2011 at 2:56pm.

The perimeter of a rectangle is 80m. The length is 7m more than twice and width. Find the dimensions.

I would appreciate help with the steps so I can practice it for the my next problem. Thanks.

- algebra -
**Marth**, Sunday, January 2, 2011 at 3:00pmLet l be the length.

Let w be the width.

"The length is 7m more than twice and width."

l = 2w+7

The perimeter of a rectangle is P=2(l+w).

Substitute in l=2w+7 for the length.

80 = 2(2w+7+w)

80 = 2(3w+7)

80 = 6w + 14

66 = 6w

w = 11

l = 2w+7

l = 29

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