algebra
posted by hawkins on .
can someone please help me.
The perimeter of a rectangle is 80m. The length is 7m more than twice and width. Find the dimensions.
I would appreciate help with the steps so I can practice it for the my next problem. Thanks.

Let l be the length.
Let w be the width.
"The length is 7m more than twice and width."
l = 2w+7
The perimeter of a rectangle is P=2(l+w).
Substitute in l=2w+7 for the length.
80 = 2(2w+7+w)
80 = 2(3w+7)
80 = 6w + 14
66 = 6w
w = 11
l = 2w+7
l = 29