Posted by Suha on Sunday, January 2, 2011 at 10:30am.
The solubility of Ag2S is 2.48x10^15 mol/dm3. Calculate its solubility product.

Chemistry  bobpursley, Sunday, January 2, 2011 at 11:30am
Write the equation:
Ag2S<<>>2Ag+ + S when in equilibrium
ksp= [Ag+]^2 [S]/[Ag2S]
ksp= (2x)^2 (x)/x
you are given x as 2.48E15
solve for ksp
=4x^2