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Posted by on Sunday, January 2, 2011 at 10:30am.

The solubility of Ag2S is 2.48x10^-15 mol/dm3. Calculate its solubility product.

  • Chemistry - , Sunday, January 2, 2011 at 11:30am

    Write the equation:

    Ag2S<<>>2Ag+ + S-- when in equilibrium

    ksp= [Ag+]^2 [S--]/[Ag2S]

    ksp= (2x)^2 (x)/x

    you are given x as 2.48E-15

    solve for ksp
    =4x^2

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