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December 20, 2014

December 20, 2014

Posted by **Kim** on Saturday, January 1, 2011 at 9:10pm.

This is what I have so far dont know where to go from here

4h^2 + 8h - 5

(4h^2-2h) + (10h-5)

2h(h-5) + -5(2h-1)

cant figure out what to do next

- Algebra -
**Marth**, Saturday, January 1, 2011 at 9:52pm4h^2 + 8h - 5 is a quadratic, so do not factor by grouping. It has only 2 factors.

Try (2h + _)(2h - _). (The other possibility is (4h +/- _)(h +/- _).

(2h + 5)(2h - 1) gives the +8h we need.

- Algebra -
**Henry**, Sunday, January 2, 2011 at 5:40pm4h^2 + 8h - 5.

Use the AC Method:

A*C = 4*-5 = -20 = -2*10.

4h^2 + (-2h + 10h) - 5,

Group the 4 terms into 2 factorable

pairss:

(4h^2 - 2h) + (10h - 5),

2h(2h - 1) + 5(2h - 1),

Factor out (2h - 1):

(2h - 1)(2h + 5).

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