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April 1, 2015

April 1, 2015

Posted by **stephen** on Saturday, January 1, 2011 at 6:23pm.

- hang on -
**Damon**, Saturday, January 1, 2011 at 6:31pmaargh, did this yesterday, going to look

- math -
**bobpursley**, Saturday, January 1, 2011 at 6:34pm - oh well, did it again -
**Damon**, Saturday, January 1, 2011 at 6:37pmh^2 = 90^2 + x^2

h is hypotenuse

x is distance from third

where x = (45-20t) so dx/dt = -20

2 h dh/dt = 2 x dx/dt

dh/dt = (x/h) (-20)

at t = 0, x = 45 and h = 100.6

so

dh/dt = -8.94

- Thanks Bob - I did it differently yesterday, same answer -
**Damon**, Saturday, January 1, 2011 at 6:41pm - math -
**Damon**, Saturday, January 1, 2011 at 6:42pmx^2 = (45-20*t)^2 + 90^2

2 x dx/dt = 2 *(45-20t) (-20)

at x=sqrt(45^2+90^2) when t = 0

2 (100.6) dx/dt = 90*-20

dx/dt = -8.94 ft/s

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