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December 3, 2016
Posted by **Ka** on Saturday, January 1, 2011 at 5:18pm.

x(-x^3-4x^2+3x+18) (using synthetic division please.) Thank You.

- Math -
**Marth**, Saturday, January 1, 2011 at 5:31pmThe possible rational factors are (+/-){factors of 18}/{factors of 1}: 18 is the coefficient of the x^0 term, and 1 is the coefficient of the greatest power of x - x^3 term.

= (+/-){1, 2, 3, 6, 9, 18}/{1} = (+/-){1, 2, 3, 6, 9, 18}.

Try factors using synthetic division until you find one that works. After, you will be left with a quadratic which is more easily factored. - Math -
**Henry**, Monday, January 3, 2011 at 4:51pmX(-X^3 - 4X^2 + 3X + 18).

It was determined by trial and error

that when X = 2, the quantity in paren-

thesis = 0. Therefore,

x = 2,

x-2 = 0,

Using synthetic division:

(-X^3 - 4X^2 + 3X + 18) / (X - 2) =

-X^2 - 6X - 9,

Our Eq is now:

X(X - 2)(-X^2 - 6X - 9),

The trinomial = 0 when X = -3,

X = -3,

X + 3 = 0,

Using synthetic division:

(-X^2 - 6X - 9) / (X + 3) = -X - 3,

Factored Eq: X(X - 2)(X + 3)(-X - 3).