Post a New Question

physics

posted by on .

Three spheres, each with a negative chrge of 4.0x10^6C, are fixed at the vertices of an equilateral triangle whose sides are 0.20 m long. Calculate the magnitude and direction of the net electric force on each spehere.



i used this: (K)Cos30((4.0*10-6)*2)/(0.2*2)

and i get 3.1 every time...

  • answered twice already - ,

    I have answered this one twice as well
    ^ means exponent
    times 2 for two spheres forcing third

  • physicshttp://www.jiskha.com/display.cgi?id=1293915742#1293915742.1293916579 - ,

    http://www.jiskha.com/display.cgi?id=1293915742#1293915742.1293916579

  • physics - ,

    thank you for responding:

    i did:

    (9.0*10^9)cos30((4.0*10^-6)^2)/(0.2^2)

    using this i got 3.1. so then i need to double it because it's two spheres. right?


    and sorry about the formula in the question. i confused my self with the "times" and "exponent".

  • physics - ,

    cos 30 = 1/2

    so 9*16 /4 and figure out decimal= 36 *10^(9-12+2)

    = 3.6

  • physics - ,

    oh sorry, cos 30 = .866
    so
    3.6*.866/.5

    6.24

  • physics - ,

    thank you. this was very helpful.

  • physics - ,

    You are welcome.

  • physics - ,

    Im working on this same question too and i cant figure out how you got the .5 when doing 3.6*.866/.5 ??? because i know the answer is correct, is it because the net force goes through the middle?

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question