Determine the frequency of y = 2 - 3 cos 10x. (nearest tenth)
Please help
frequency is applied to a trig function which is dependent on time, not position.
If you had y=2-3cos10t, then frequency would be found by 2PI*frequency=10
and f= 1.59rad/sec
I am wondering if your teacher is using a private definition of frequency.
To determine the frequency of the function y = 2 - 3 cos 10x, we need to understand the relationship between frequency and the period of a cosine function.
The general form of a cosine function is given by:
y = A cos (Bx + C)
In this case, A = -3, B = 10, and C = 0.
The period of a cosine function is given by the formula:
Period = 2π / |B|
Substituting the value of B into the formula, we get:
Period = 2π / |10|
Simplifying, we have:
Period = π / 5
The frequency of a function is the reciprocal of its period. Therefore, the frequency can be found by taking the reciprocal of the period:
Frequency = 1 / Period
Substituting the value of the period into the formula, we get:
Frequency = 1 / (π / 5)
To calculate the frequency to the nearest tenth, we can divide 1 by the value of π/5:
Frequency = 1 / (π / 5) ≈ 0.637
Therefore, the frequency of the function y = 2 - 3 cos 10x is approximately 0.6 (nearest tenth).