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April 23, 2014

April 23, 2014

Posted by **george** on Friday, December 31, 2010 at 8:08pm.

- related rate problem -
**bobpursley**, Friday, December 31, 2010 at 8:33pmWell, 4 seconds after crossing, the train has traveled 240 m. Draw your figure, lets are 60, 240, and the hypotenuse is L=sqrt (60^2+240^2)

But in general, l^2=x^2+60^2

2L*dL/dt=2x dx/dt

you are solveing for dL/dt, you know x, dx/dt, and L.

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