Post a New Question


posted by on .

At the instant when the radius of a cone is 3 inches, the volume of the cone is increasing at the rate of 28.27433388 cubic inches per minute. If the height is always 3 times the radius, find the rate of change of the radius at that instant?

  • calculus - ,

    For a cone, V = (1/3)(pi)(r^2)(h).

    But h=3r, so V = (pi)r^3.

    Differentiate with respect to time.

    dV/dt = (3pi)(r^2)(dr/dt)

    dr/dt = (3pi)(r^2)/(dV/dt)

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question