Posted by **chip** on Thursday, December 30, 2010 at 11:35am.

whats the vertex of 4y^2+4y-16x+13=0?

- math -
**Reiny**, Thursday, December 30, 2010 at 11:51am
rearrange, then complete the square ....

16x = 4y^2 + 4y + 13

4x = y^2 + y **+ 1/4 - 1/4** + 13/4

4x = (y + 1/2)^2 -1/4 + 13/4

4x = (y+1/2)^2 - 3

x = (1/4)(y + 1/2)^2 - 3/4

can you read the vertex from that?

- math -
**chip**, Thursday, December 30, 2010 at 11:55am
so is it (-3/4,-1/2)?

- math -
**Reiny**, Thursday, December 30, 2010 at 12:28pm
yes, good for you to notice that you had to read the x and y in inverse form.

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