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July 29, 2014

July 29, 2014

Posted by **sue** on Thursday, December 30, 2010 at 4:12am.

Find the vertex of 4y^2+4y-16x+13=0

Find the center of an ellipse 9x^2+4y^2-36x-24y-36=0

Find an ellipse with minor axis of 8 and vertices at (-9,3),(7,3)

- precal help -
**Damon**, Thursday, December 30, 2010 at 5:57amIn all of these problems complete the square, then look at standard form of conic section.

For example to find the center of the ellipse

Find the center of an ellipse 9x^2+4y^2-36x-24y-36=0

9 x^2 -36 x -36 = -4 y^2 + 24 y

(-9/4) x^2 + 9 x + 9 = y^2 -6 y

(-9/4) x^2 + 9 x + 18 = y^2 -6 y + 9

(-9/4) x^2 + 9 x + 18 = (y-3)^2

x^2 - 4 x - 8 = (-4/9) (y-3)^2

x^2 - 4 x = (-4/9) (y-3)^2 + 8

x^2 - 4 x + 2 = (-4/9) (y-3)^2 + 10

(x-2)^2 + (4/9) (y-3)^2 = 10

You can see right now that center is at (2,3)

(x-2)^2/10 + (y-3)^2/(90/4) = 1

- error -
**Damon**, Thursday, December 30, 2010 at 6:00amx^2 - 4 x = (-4/9) (y-3)^2 + 8

x^2 - 4 x + 4 = (-4/9) (y-3)^2 + 12

(x-2)^2 + (4/9) (y-3)^2 = 12

You can see right now that center is at (2,3)

(x-2)^2/12 + (y-3)^2/(27) = 1

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