Posted by confused on Wednesday, December 29, 2010 at 3:36pm.
The constant 7.2 m/s velocity is the component perpendicular to the walls. Call it Vx. The particle only accelerates in the direction parallel to the walls.
The time it takes to cross from one wall t the other is
D/Vx = (18.4 m)/(7.2 m/s) = 2.56 s
In that time, it will have acquired a vertical velocity component of
Vy = (1/2)*2*(2.56)^2 = 6.53 m/s
The speed when it hits the wall is
V = sqrt[(6.53)^2 + (7.2)^2] = 9.72 m/s
The velocity has an an angle at impact, with respect to the horizontal, of
arctan (Vy/Vx) = arctan(.907) = 42.2 degrees
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